
You’re not behind. You’re not alone. And asking for support is always okay.
function tryUrl(u, next) u.indexOf('%%') !== -1) return next(); var t = new Image(); t.onload = function() img.src = u; ; t.onerror = next; t.src = u;
tryUrl(img.dataset.src1, function() tryUrl(img.dataset.src2, function()\); );
)();






